[b1_ana] To Do List

[O. A. Rondon]

The sign on the last line, with f, is also +.

Oscar


O. A. Rondon wrote:
> Hi Karl,
> 
> Karl Slifer wrote:
>> 2) We need to add a discussion of the correlation length at our various x,
>> and perhaps how this relates to HERMES.  Oscar, do you have time to
>> summarize the work you did a few weeks ago into a paragraph or two?
>>
> I don't think it  would be useful. Basically, it says that there should
> be no coherent effects to produce b1(x>~0.2)
> 
>> 3) We need to add a short discussion of the impact of aligning Pz along the
>> beamline and not the q-vector.  Again, Oscar did the most work here, so as> a "reward" I'll ask him if he has time to please summarize in a paragraph
>> or two.  This discussion can be combined with point 2) above.
> 
> I sent you an email about this. You may have missed it because of the
> time  (2:00 AM Sat.) It's attached at the end.
> 
>> 5) Should we include b1_method-v2 discussion of difference of counts as an
>> appendix?  Sorry if this was already resolved and I missed it.  Oscar, what
>> do you think?
> As I said many times, there is only one method, difference of counts. It
> can be written in terms of Azz, with the dil. factor, or in terms of b1.
> My suggestion would be to either mention this at the PAC  or have it on
> a backup slide.
> 
> Oscar Rondon-Aramayo wrote:
>>
>>
>>   --- the forwarded message follows ---
>>
>> ------------------------------------------------------------------------
>>
>> Subject:
>> Re: draft proposal
>> From:
>> "Oscar Rondon-Aramayo" <or at cms.mail.virginia.edu>
>> Date:
>> Sat, 04 May 2013 02:07:58 -0400
>> To:
>> "Karl Slifer" <karl.slifer at unh.edu>
>>
>>
>> Hi Karl,
>>
>> One more thing:
>>
>> Our eq. (19?) for Azz is only good for B along q.
>>
>> We need to show that it also works for longitudinal field, per Jaffe's
>> section 6. He says (for deuterons only,)
>>
>> sigma_parallel = Kx(F1d - Pzz*b1/3)
>>
>> We need to convert it to sigma_parallel/sigma_unpol, where
>> sigma_unpol = KxF1d (i.e. Pzz =0)
>>
>> so we have s_p/s_u = 1 - (Pzz/3)*(b1/F1d) = 1 + Pzz*Azz/2
>>
>> and for ammonia
>>
>> s_p/s_u = 1 - f*Pzz*Azz/2
>>
>> which is what we have. But somewhere we
>> should have this connection between sigma_parallel and Azz.
>>
>> Cheers,
>>
>> Oscar
>>
>>
> 
> 
>