[Frost] Question

[Steffen Strauch]

Dear Michael,

It is important that the weights in the moments in the denominator contain an additional factor of Q compared to the numerator.

I don’t think there is a typo here. If you compare on page 4 the two sets of moment ratios, you see that the first set already contains Q in the integral.  Weighing the cos(alpha) moment with an additional factor of Q, gives you the Q^2 in the integral of the numerator in the second set.  The denominator of the first set does not contain any Q in the integral.  So, an additional factor of Q^2 in the weight of the moment gives you the Q^2 in the integral of the denominator of the second set.

For the correct expression that the extracted value is the weighted average of P and not Q*P.

Thanks,
Steffen



> On Aug 17, 2016, at 12:06 PM, Michael Dugger <dugger at jlab.org> wrote:
> 
> 
> Steffen,
> 
> On last line of slide 4 and slide 5 of your pdf:
> 
> https://www.jlab.org/Hall-B/secure/g9/g9_strauch/mtg/FROST_meeting_2016_08_18.pdf
> 
> you show on the left hand side
> 
> Y_{Q cos\alpha}/Y_{Q^2 cos^2 \alpha},
> 
> where there is a factor of Q in the numerator and a factor of Q^2 in the denominator.
> 
> However, in the middle of the line you have Q^2 in both the numerator and denominator. Is there a typo?
> 
> If you have Q^2 in both the numerator and denominator, the expression will not work.
> 
> Take care,
> Michael
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