[Frost] Question

[Barry Ritchie]

Steffen, just a note: I should think that another possible worry arises in the approach you’ve outlined by the use of non-orthogonal polynomials. For any expansion of the yield in terms of powers of cos α , one should use the (orthogonal) Legendre polynomials, Pn (cos2α), I’d think, for the same reason one uses the (orthogonal)  cos mα terms in the Fourier moment method. Otherwise, since cos2α is not orthogonal to cos α, the cos2α yield term will automatically be picking up pieces both of the zeroth-order P0 (cos α)and the cos2α part of the fourth-order P4 (cos α) term. For a perfect detector (meaning perfect efficiency and 4π acceptance), this is not crucial, but I would worry that it manifestly would be problematic for the real CLAS detector.  ---BGR

Professor Barry G. Ritchie
Department of Physics
Arizona State University
Tempe, AZ 85287-1504

Phone: (480) 965-4707
Fax: (480) 965-7954

From: Frost [mailto:frost-bounces at jlab.org] On Behalf Of Steffen Strauch
Sent: Wednesday, August 17, 2016 3:17 PM
To: Michael Dugger <dugger at jlab.org>
Cc: frost at jlab.org
Subject: Re: [Frost] Question

Dear Michael,

Yes, this is what I originally suggested for the experimentally determined sums over all events.

In the meantime, I think I need to revise the expressions and the numerator sum should read: cos(\alpha) and the denominator sum should read Q cos^2(\alpha).  This and the earlier expressions give the same results for constant background or if the observable does not change over the kinematic bin; like in our simplified examples.  Practically, the differences will be small.  However, when there are variations of the observable or of the background over a large bin (like in the double-pion case), the latter expressions give in my opinion results for the observable which are more meaningful.

I will update my slides and we can discuss this more during tomorrow’s meeting.

Steffen


On Aug 17, 2016, at 1:21 PM, Michael Dugger <dugger at jlab.org<mailto:dugger at jlab.org>> wrote:


Steffen,

I just want to make sure I understand.

You weight each numerator event by

Q cos(\alpha)

and each denominator event by

[Q cos(\alpha)]^2 .

Is this correct?

Take care,
Michael

On Wed, 17 Aug 2016, Steffen Strauch wrote:


Dear Michael,

It is important that the weights in the moments in the denominator contain an additional factor of Q compared to the numerator.

I don’t think there is a typo here. If you compare on page 4 the two sets of moment ratios, you see that the first set already contains Q in the integral.  Weighing the cos(alpha) moment with an additional factor of Q, gives you the Q^2 in the integral of the numerator in the second set.  The denominator of the first set does not contain any Q in the integral.  So, an additional factor of Q^2 in the weight of the moment gives you the Q^2 in the integral of the denominator of the second set.

For the correct expression that the extracted value is the weighted average of P and not Q*P.

Thanks,
Steffen




On Aug 17, 2016, at 12:06 PM, Michael Dugger <dugger at jlab.org<mailto:dugger at jlab.org>> wrote:


Steffen,

On last line of slide 4 and slide 5 of your pdf:

https://www.jlab.org/Hall-B/secure/g9/g9_strauch/mtg/FROST_meeting_2016_08_18.pdf<https://urldefense.proofpoint.com/v2/url?u=https-3A__www.jlab.org_Hall-2DB_secure_g9_g9-5Fstrauch_mtg_FROST-5Fmeeting-5F2016-5F08-5F18.pdf&d=CwMFaQ&c=AGbYxfJbXK67KfXyGqyv2Ejiz41FqQuZFk4A-1IxfAU&r=NC99X3Muut85jp1nyEEaKzrqGMedseDv3USQMbrzzMU&m=uKTOtlnnx_ZYFBxdgkWlssxnYsmNeTBkCDiI5B_qXYI&s=rNmvyekg4GCUDmS6Ot0NLHq7ce474-Bn80L5NOU7gko&e=>

you show on the left hand side

Y_{Q cos\alpha}/Y_{Q^2 cos^2 \alpha},

where there is a factor of Q in the numerator and a factor of Q^2 in the denominator.

However, in the middle of the line you have Q^2 in both the numerator and denominator. Is there a typo?

If you have Q^2 in both the numerator and denominator, the expression will not work.

Take care,
Michael
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