<html><head><style type='text/css'>p { margin: 0; }</style></head><body><div style='font-family: arial,helvetica,sans-serif; font-size: 12pt; color: #000000'>Yes, I would like to see it versus angles of detected particles, not the missing ones.<br><br><div><span name="x"></span>-Eugene<span name="x"></span><br></div><br><hr id="zwchr"><blockquote style="border-left:2px solid #1010FF;margin-left:5px;padding-left:5px;color:#000;font-weight:normal;font-style:normal;text-decoration:none;font-family:Helvetica,Arial,sans-serif;font-size:12pt;"><b>From: </b>"Irene Zonta" <irene.zonta@roma2.infn.it><br><b>To: </b>"Eugene Pasyuk" <pasyuk@jlab.org><br><b>Cc: </b>"g14 run" <g14_run@jlab.org>, "A.M. Sandorfi" <sandorfi@jlab.org>, "Annalisa D'Angelo" <annalisa.dangelo@roma2.infn.it>, daoh@andrew.cmu.edu, "Peng Peng" <pp9e@virginia.edu>, hlu@jlab.org<br><b>Sent: </b>Thursday, April 24, 2014 10:08:49 AM<br><b>Subject: </b>Re: mmass vs polar angle<br><br>Hi Eugene,<div>the plots refers to the reaction gamma d -> pi- p p ,where we imposed the detection of 1 piminus and 2 protons by using a cut around 0 on the gamma d -> pi- p p Missing Mass. </div><div>I then plotted the missing mass for gamma d -> pi- p (X) which then should correspond to the other proton, as a function of the polar angle of the missing proton. The reference frame is the lab. </div><div>Do you want me to repeat the procedure for the missing pion? Or do you want to see the missing mass versus the measured angles instead of the missing ones?</div><div><br></div><div>Irene</div><div><br><div><div>On Apr 24, 2014, at 4:00 PM, Eugene Pasyuk <<a href="mailto:pasyuk@jlab.org" target="_blank">pasyuk@jlab.org</a>> wrote:</div><br class="Apple-interchange-newline"><blockquote><div><div>Hi Irene,<div><br></div><div>Looks nice. A couple of questions.</div><div>For which particle is this angle or you put both pion and proton angle in the same histogram? Is it the lab angle or center of mass angle? It would be good to see this in a lab frame separately for pion angle and for proton angle. Can you do this?</div><div><br></div><div>Thanks,<br><br><div>-Eugene<br></div><br><hr id="zwchr"><blockquote><b>From: </b>"Irene Zonta" <<a href="mailto:irene.zonta@roma2.infn.it" target="_blank">irene.zonta@roma2.infn.it</a>><br><b>To: </b>"A.M. Sandorfi" <<a href="mailto:sandorfi@jlab.org" target="_blank">sandorfi@jlab.org</a>>, <a href="mailto:pasyuk@jlab.org" target="_blank">pasyuk@jlab.org</a>, "Annalisa D'Angelo" <<a href="mailto:annalisa.dangelo@roma2.infn.it" target="_blank">annalisa.dangelo@roma2.infn.it</a>>, <a href="mailto:daoh@andrew.cmu.edu" target="_blank">daoh@andrew.cmu.edu</a>, "Peng Peng" <<a href="mailto:pp9e@virginia.edu" target="_blank">pp9e@virginia.edu</a>>, <a href="mailto:hlu@jlab.org" target="_blank">hlu@jlab.org</a><br><b>Cc: </b>"g14 run" <<a href="mailto:g14_run@jlab.org" target="_blank">g14_run@jlab.org</a>><br><b>Sent: </b>Thursday, April 24, 2014 9:33:36 AM<br><b>Subject: </b>mmass vs polar angle<br><br>Dear all,<div>here is the result of the test that Eugene asked for, form the reaction gamma d -> pi- p (X). It looks like the correction is appropriate for every angle.</div><div><br></div><div>Cheers</div><div><br></div><div>Irene<br><div><br class="Apple-interchange-newline"><blockquote><img height="472" width="696" src="cid:E0116C8E-A3D3-4CC2-A5C2-FCD1F1BDFEA9@roma2.infn.it"><img height="472" width="696" src="cid:050F19E0-906D-4ADF-9423-D44CB4698383@roma2.infn.it"></blockquote></div></div></blockquote></div></div></div></blockquote></div><br></div></blockquote><br></div></body></html>