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<p class="MsoNormal">Hi Alessandra,<o:p></o:p></p>
<p class="MsoNormal">A few comments might help:<o:p></o:p></p>
<ol style="margin-top:0in" start="1" type="1">
<li class="MsoListParagraph" style="margin-left:0in;mso-list:l1 level1 lfo3">I constructed that table which Tsuneo forwarded in order to define the separation of the beam-entrance and beam-exit kel-F widows, for the sake of comparing with and calibrating the
vertex reconstruction. <o:p></o:p></li><li class="MsoListParagraph" style="margin-left:0in;mso-list:l1 level1 lfo3">The dimensions in that table do not define the effective HD length. That is determined by the amount of gas that was condensed. The silver (21a) target was about 4 cm long, and not
a right cylinder, due to problems when the target was formed. The other two had smooth injections and appear to be right-cylinders of 5 cm in length. These conclusions come from a comparison between the vertex image and a calculation of the amount of HD gas
that was condensed. <o:p></o:p></li><li class="MsoListParagraph" style="margin-left:0in;mso-list:l1 level1 lfo3">The aluminum wire diameter and density are well known (yes, I measured them), but the lengths are only approximately known. (Imagine trying to position a thousand hairs, one by one.)
<o:p></o:p></li></ol>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal">Andy<o:p></o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal" style="margin-bottom:12.0pt"><b><span style="font-size:12.0pt;color:black">From:
</span></b><span style="font-size:12.0pt;color:black">G14_run <g14_run-bounces@jlab.org> on behalf of Alessandra FIlippi via G14_run <g14_run@jlab.org><br>
<b>Date: </b>Friday, May 5, 2023 at 10:23 AM<br>
<b>To: </b>Tsuneo Kageya <kageya@jlab.org><br>
<b>Cc: </b>g14_run@jlab.org <g14_run@jlab.org>, Tsuneo Kageya <kageya@jlab.org><br>
<b>Subject: </b>[G14_run] [EXTERNAL] Re: Locations of the Kel-F windows<o:p></o:p></span></p>
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<p class="MsoNormal">Hi Tsuneo,<br>
<br>
><br>
> Ciao Alessandra,<br>
><br>
><br>
> here is an expanded view of Fig. 28 (attached to this email).<br>
><br>
> I would like to suggest to show z range -15 < z < -5 cm for Fig. 28.<br>
><br>
> I don't think we need the range of z > -5 cm.<br>
<br>
ok, I just put there what I had ready, I can zoom it a little bit.<br>
<br>
><br>
> We can see the following things from the figure.<br>
><br>
<br>
aaaah, now I understand... the "Aluminum wire" is that sort of messy hank<br>
inside the cell! I believed the wires were tensioned along the walls of<br>
the cylinder. So, they make an overall contribution in the central part<br>
which could potentially be relevant, it makes sense.<br>
We know the density of this wire, has anybody ever weighted the total<br>
amount of Al mass in this region? its length and its cross section, to be<br>
more quantitative?<br>
I'll correct the text accordingly. Sorry my bad, I never understood this<br>
was the real target structure.<br>
<br>
><br>
> (1) Relative positions of three Kel-F windows for Gold2 (19b) and Empty<br>
> (21a).<br>
><br>
> I am attaching the info. about target cell 19b and 21a.<br>
><br>
><br>
> (a) The positions of downstream Kel-F windows for Gold2 and Empty are<br>
> close at Fig. 28.<br>
><br>
><br>
> (b) As can see L1 on the table of the attacment, the difference of 96.21<br>
> - 95.74 = 0.47 mm<br>
<br>
ok. Do we care about what happens in the very upstream region, L4?<br>
I assumed not.<br>
<br>
><br>
> is seen at the exit windows at Fig. 28.<br>
><br>
><br>
> (c) L4 difference shown on the table as 36.90 - 34.10 = 2.8 mm can be<br>
> seen at the entrande windows at Fig.28.<br>
><br>
><br>
<br>
ok<br>
<br>
> (2) Small diffence of downstream Kel-F positions between Silver (21a) and<br>
> Empty (21a) can be observed as 1 mm or so<br>
><br>
> which could be negligible.<br>
><br>
<br>
yes, I believe the important information is how long is the "HD" volume,<br>
that is l = L1-L3-L4<br>
<br>
><br>
> In order to understand eq. 35, can you define, l_empty, l_gold, Z<br>
> ^gold_KelF1 and Z^empty_KelF1 ?<br>
><br>
> What are their equivalent numbers at the table ?<br>
<br>
l_{cell} = L1-L3-L3 - they differ for about 1 mm (61.63-59.20 mm), you can<br>
see them in the table. This means that the HD length is slightly different<br>
in the two cases.<br>
Z^whatever_KelF1 is the z I get from a gaussian fit of the entrance window<br>
peak for each cell. I need this and the HD length (see above) to write the<br>
transformation for the z coordinate, to "align" the targets, ie bring the<br>
gold2 entrance window to level up with the empty target entrance. These<br>
are the values reported on the table.<br>
Cheers,<br>
Alessandra<br>
<br>
<br>
<br>
><br>
> Ciao, Tsuneo Kageya.<br>
><br>
><br>
><br>
<br>
<br>
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