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I just forgot to include g14_run to respond to the email from Alessandra the last Friday and am sending it to</div>
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everybody.</div>
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Ciao Alessandra,</div>
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thank you for the updates.</div>
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I am still reading your email and note.</div>
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I think we may have the following conclusions about empty target subtractions for your case.</div>
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(1) If we are interested only in the range of your z vertex cut of -9.5 < z < -5.8 cm and entrance and exit Kel-F windows' contributions could be </div>
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negligible to this z <span style="font-family: Calibri, Arial, Helvetica, sans-serif; font-size: 12pt; color: rgb(0, 0, 0);">
range, the empty target distributions normalized with the downstream Kel-F can be used without complicated</span></div>
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calculations, I think.</div>
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(2) We can use the factors <span class="x_ContentPasted0 x_ContentPasted1" style="font-family: CMMI12; font-size: 12pt; margin: 0px; text-decoration: none; background-color: rgb(255, 255, 255);">ñ</span><span class="x_ContentPasted0 x_ContentPasted1" style="font-family: CMMI8; font-size: 8pt; margin: 0px; vertical-align: 4pt; text-decoration: none; background-color: rgb(255, 255, 255);">rel<span class="x_Apple-converted-space x_ContentPasted0" style="margin:0px"></span></span><span class="x_ContentPasted0 x_ContentPasted1" style="font-family: CMR12; font-size: 12pt; margin: 0px; text-decoration: none; background-color: rgb(255, 255, 255);">=
0</span><span class="x_ContentPasted0 x_ContentPasted1" style="font-family: CMMI12; font-size: 12pt; margin: 0px; text-decoration: none; background-color: rgb(255, 255, 255);">.</span><span class="x_ContentPasted0 x_ContentPasted1" style="font-family: CMR12; font-size: 12pt; margin: 0px; text-decoration: none; background-color: rgb(255, 255, 255);">7
(</span>in your note) for Gold target (19b) and <span class="x_ContentPasted0 x_ContentPasted2" style="font-family: CMMI12; font-size: 12pt; margin: 0px; text-decoration: none; background-color: rgb(255, 255, 255);">
ñ</span><span class="x_ContentPasted0 x_ContentPasted2" style="font-family: CMMI8; font-size: 8pt; margin: 0px; vertical-align: 4pt; text-decoration: none; background-color: rgb(255, 255, 255);">rel<span class="x_Apple-converted-space x_ContentPasted0" style="margin:0px"></span></span><span class="x_ContentPasted0 x_ContentPasted2" style="font-family: CMR12; font-size: 12pt; margin: 0px; text-decoration: none; background-color: rgb(255, 255, 255);">=
1.0 </span>for the Silver target (21a) to be multiplied to the empty</div>
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distributions for the subtractions.</div>
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(3) Still we may need to shift the z vertex distributions for 21a and 10b target cell positions like you are doing in the note.</div>
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<span style="font-family: Calibri, Arial, Helvetica, sans-serif; font-size: 12pt; color: rgb(0, 0, 0);"> Discussions on the eq. 36 - 38 are for the wider cuts like -10 < z < -2 cm, I think. Probably you got the ways of calculations from Andy's</span></div>
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<span style="font-family: Calibri, Arial, Helvetica, sans-serif; font-size: 12pt; color: rgb(0, 0, 0);"> notes. I used the 0.903 for the subtractions for Gold target with the wider z cut. </span></div>
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<div class="x_elementToProof" style="background-color: rgb(255, 255, 255);"><font face="Calibri, Arial, Helvetica, sans-serif" size="3" style="color: rgb(0, 0, 0);"> I will try to give you more detailed info. like Al wire's diameter and total </font><font face="Calibri, Arial, Helvetica, sans-serif" style="color: rgb(0, 0, 0);"><span style="">number<font size="3"> of
wires later.</font></span></font></div>
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<div class="x_elementToProof" style="background-color: rgb(255, 255, 255);"><font face="Calibri, Arial, Helvetica, sans-serif" style="color: rgb(0, 0, 0);"><span style=""><font size="3"> Ciao, Tsuneo Kageya.</font></span></font></div>
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<div id="x_divRplyFwdMsg" dir="ltr"><font face="Calibri, sans-serif" style="font-size: 11pt; color: rgb(0, 0, 0);"><b>From:</b> filippi@to.infn.it <filippi@to.infn.it><br>
<b>Sent:</b> Friday, May 5, 2023 10:22 AM<br>
<b>To:</b> Tsuneo Kageya <kageya@jlab.org><br>
<b>Cc:</b> alessandra filippi <filippi@to.infn.it>; g14_run@jlab.org <g14_run@jlab.org>; Tsuneo Kageya <kageya@jlab.org><br>
<b>Subject:</b> [EXTERNAL] Re: Locations of the Kel-F windows</font>
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<div class="x_PlainText">Hi Tsuneo,<br>
<br>
><br>
> Ciao Alessandra,<br>
><br>
><br>
> here is an expanded view of Fig. 28 (attached to this email).<br>
><br>
> I would like to suggest to show z range -15 < z < -5 cm for Fig. 28.<br>
><br>
> I don't think we need the range of z > -5 cm.<br>
<br>
ok, I just put there what I had ready, I can zoom it a little bit.<br>
<br>
><br>
> We can see the following things from the figure.<br>
><br>
<br>
aaaah, now I understand... the "Aluminum wire" is that sort of messy hank<br>
inside the cell! I believed the wires were tensioned along the walls of<br>
the cylinder. So, they make an overall contribution in the central part<br>
which could potentially be relevant, it makes sense.<br>
We know the density of this wire, has anybody ever weighted the total<br>
amount of Al mass in this region? its length and its cross section, to be<br>
more quantitative?<br>
I'll correct the text accordingly. Sorry my bad, I never understood this<br>
was the real target structure.<br>
<br>
><br>
> (1) Relative positions of three Kel-F windows for Gold2 (19b) and Empty<br>
> (21a).<br>
><br>
> I am attaching the info. about target cell 19b and 21a.<br>
><br>
><br>
> (a) The positions of downstream Kel-F windows for Gold2 and Empty are<br>
> close at Fig. 28.<br>
><br>
><br>
> (b) As can see L1 on the table of the attacment, the difference of 96.21<br>
> - 95.74 = 0.47 mm<br>
<br>
ok. Do we care about what happens in the very upstream region, L4?<br>
I assumed not.<br>
<br>
><br>
> is seen at the exit windows at Fig. 28.<br>
><br>
><br>
> (c) L4 difference shown on the table as 36.90 - 34.10 = 2.8 mm can be<br>
> seen at the entrande windows at Fig.28.<br>
><br>
><br>
<br>
ok<br>
<br>
> (2) Small diffence of downstream Kel-F positions between Silver (21a) and<br>
> Empty (21a) can be observed as 1 mm or so<br>
><br>
> which could be negligible.<br>
><br>
<br>
yes, I believe the important information is how long is the "HD" volume,<br>
that is l = L1-L3-L4<br>
<br>
><br>
> In order to understand eq. 35, can you define, l_empty, l_gold, Z<br>
> ^gold_KelF1 and Z^empty_KelF1 ?<br>
><br>
> What are their equivalent numbers at the table ?<br>
<br>
l_{cell} = L1-L3-L3 - they differ for about 1 mm (61.63-59.20 mm), you can<br>
see them in the table. This means that the HD length is slightly different<br>
in the two cases.<br>
Z^whatever_KelF1 is the z I get from a gaussian fit of the entrance window<br>
peak for each cell. I need this and the HD length (see above) to write the<br>
transformation for the z coordinate, to "align" the targets, ie bring the<br>
gold2 entrance window to level up with the empty target entrance. These<br>
are the values reported on the table.<br>
Cheers,<br>
Alessandra<br>
<br>
<br>
<br>
><br>
> Ciao, Tsuneo Kageya.<br>
><br>
><br>
><br>
<br>
<br>
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