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Hi Holly,<br>
<br>
Also do not forget that integral field that is used may not be
exactly what we <br>
have in real life. So, new simulations may be needed to get
parametrization correct.<br>
<br>
Stepan<br>
<div class="moz-cite-prefix">On 1/9/15 12:03 PM, Holly Vance wrote:<br>
</div>
<blockquote
cite="mid:CAM9TiFPi5-N7QZjZk3hMfVeMUx+PcteCvBmwTvbPTDXkUDF2yg@mail.gmail.com"
type="cite">
<div dir="ltr">Hi Michel,
<div><br>
</div>
<div>Thank you for your response. Indeed, you are correct-it is
misleading to write cluster energy since what I used was the
thrown monte carlo energy. FX sent me some suggestions for
checking the residuals (phi_calc - phi_generated), and the
actual resolution will contain the spread from the position
and energy as measured. It is very nice to see that all of
this supports the plots from simulation in the HPS Note
2014-001. </div>
<div><br>
</div>
<div>Respectfully,</div>
<div>Holly</div>
</div>
<div class="gmail_extra"><br>
<div class="gmail_quote">On Fri, Jan 9, 2015 at 6:17 AM, Garcon
Michel <span dir="ltr"><<a moz-do-not-send="true"
href="mailto:Michel.Garcon@cea.fr" target="_blank">Michel.Garcon@cea.fr</a>></span>
wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0
.8ex;border-left:1px #ccc solid;padding-left:1ex">
<div link="blue" vlink="purple" lang="FR">
<div>
<p class="MsoNormal">Hi Holly,</p>
<p class="MsoNormal"> </p>
<p class="MsoNormal"> <span lang="EN-US">Nice
study. It is a bit counter-intuitive to call Phi a
(projected) horizontal angle and Theta a vertical
angle, but this is a minor detail.</span></p>
<p class="MsoNormal"><span lang="EN-US"> </span></p>
<p class="MsoNormal"><span lang="EN-US">
One does expect indeed dPhi/dx = dTheta/dx ~ 1/D ~
1/1.4 m ~ 0.007 radian/cm . In the vertical
projection, the trajectory is a straight line
whatever the energy (for an ideal field), which
explains that you find no energy dependence for
Theta. In the horizontal projection, your line in
the first plot Phi vs x at 1 GeV is the same as the
light blue in Fig. 31 of HPS-Note-2014-001 (one can
see also in this figure that the slope does not
depend on energy). So everything checks nicely.</span></p>
<p class="MsoNormal"><span lang="EN-US"> </span></p>
<p class="MsoNormal"><span lang="EN-US">
I would expect B = 0 when E goes to infinity
(straight line -> x = 0 when Phi =0). But you are
right to do whatever empirical fit works in our
range.</span></p>
<p class="MsoNormal"><span lang="EN-US"> </span></p>
<p class="MsoNormal"><span lang="EN-US">
Best regards,</span></p>
<p class="MsoNormal"><span lang="EN-US">
Michel.</span></p>
<p class="MsoNormal"><span lang="EN-US"> </span></p>
<p class="MsoNormal"><span lang="EN-US">PS: by cluster
energy, do you mean deposited energy in ECal or real
energy? I would imagine the latter since you
generate particles at fixed energies; then better
not call it cluster energy, could be confusing (see
Eqs 1 and 2 of the Note).</span></p>
<p class="MsoNormal"><span lang="EN-US"> </span></p>
<p class="MsoNormal" style="text-autospace:none"><b><i><span
style="font-size:9.0pt;font-family:"Bookman
Old Style","serif";color:#4f81bd">_______________</span></i></b></p>
<p class="MsoNormal" style="text-autospace:none"><b><i><span
style="font-size:9.0pt;font-family:"Bookman
Old Style","serif";color:#4f81bd">Michel
Garçon</span></i></b></p>
<p class="MsoNormal" style="text-autospace:none"><i><span
style="font-size:9.0pt;font-family:"Bookman
Old Style","serif";color:#4f81bd">Irfu/SPhN
</span></i></p>
<p class="MsoNormal" style="text-autospace:none"><i><span
style="font-size:9.0pt;font-family:"Bookman
Old Style","serif";color:#4f81bd">CEA-Saclay,
bât. 703
</span></i></p>
<p class="MsoNormal" style="text-autospace:none"><i><span
style="font-size:9.0pt;font-family:"Bookman
Old Style","serif";color:#4f81bd">91191
Gif-sur-Yvette cedex
</span></i><span
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Roman","serif";color:#4f81bd"></span></p>
<p class="MsoNormal" style="text-autospace:none"><i><span
style="font-size:9.0pt;font-family:"Bookman
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</span></i><i><span
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style="font-size:10.0pt;font-family:"Bookman
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<p class="MsoNormal"><i><span
style="font-size:8.0pt;font-family:"Bookman
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Old Style","serif";color:#4f81bd">
<a moz-do-not-send="true"
href="tel:%2B33%201%2069%2008%2086%2023"
value="+33169088623" target="_blank">+33 1 69 08
86 23</a></span></i></p>
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