<div dir="ltr">Hi Michel,<div><br></div><div>Thank you for your response. Indeed, you are correct-it is misleading to write cluster energy since what I used was the thrown monte carlo energy. FX sent me some suggestions for checking the residuals (phi_calc - phi_generated), and the actual resolution will contain the spread from the position and energy as measured. It is very nice to see that all of this supports the plots from simulation in the HPS Note 2014-001. </div><div><br></div><div>Respectfully,</div><div>Holly</div></div><div class="gmail_extra"><br><div class="gmail_quote">On Fri, Jan 9, 2015 at 6:17 AM, Garcon Michel <span dir="ltr"><<a href="mailto:Michel.Garcon@cea.fr" target="_blank">Michel.Garcon@cea.fr</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div lang="FR" link="blue" vlink="purple">
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<p class="MsoNormal">Hi Holly,<u></u><u></u></p>
<p class="MsoNormal"><u></u> <u></u></p>
<p class="MsoNormal"> <span lang="EN-US">Nice study. It is a bit counter-intuitive to call Phi a (projected) horizontal angle and Theta a vertical angle, but this is a minor detail.<u></u><u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"><u></u> <u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"> One does expect indeed dPhi/dx = dTheta/dx ~ 1/D ~ 1/1.4 m ~ 0.007 radian/cm . In the vertical projection, the trajectory is a straight line whatever the energy (for an ideal field), which explains that
you find no energy dependence for Theta. In the horizontal projection, your line in the first plot Phi vs x at 1 GeV is the same as the light blue in Fig. 31 of HPS-Note-2014-001 (one can see also in this figure that the slope does not depend on energy). So
everything checks nicely.<u></u><u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"><u></u> <u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"> I would expect B = 0 when E goes to infinity (straight line -> x = 0 when Phi =0). But you are right to do whatever empirical fit works in our range.<u></u><u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"><u></u> <u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"> Best regards,<u></u><u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"> Michel.<u></u><u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"><u></u> <u></u></span></p>
<p class="MsoNormal"><span lang="EN-US">PS: by cluster energy, do you mean deposited energy in ECal or real energy? I would imagine the latter since you generate particles at fixed energies; then better not call it cluster energy, could be confusing (see Eqs
1 and 2 of the Note).<u></u><u></u></span></p>
<p class="MsoNormal"><span lang="EN-US"><u></u> <u></u></span></p>
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