[G14_run] mmass vs polar angle

[Eugene Pasyuk]

Yes, I would like to see it versus angles of detected particles, not the missing ones. 

-Eugene 

----- Original Message -----

> From: "Irene Zonta" <irene.zonta at roma2.infn.it>
> To: "Eugene Pasyuk" <pasyuk at jlab.org>
> Cc: "g14 run" <g14_run at jlab.org>, "A.M. Sandorfi"
> <sandorfi at jlab.org>, "Annalisa D'Angelo"
> <annalisa.dangelo at roma2.infn.it>, daoh at andrew.cmu.edu, "Peng Peng"
> <pp9e at virginia.edu>, hlu at jlab.org
> Sent: Thursday, April 24, 2014 10:08:49 AM
> Subject: Re: mmass vs polar angle

> Hi Eugene,
> the plots refers to the reaction gamma d -> pi- p p ,where we imposed
> the detection of 1 piminus and 2 protons by using a cut around 0 on
> the gamma d -> pi- p p Missing Mass.
> I then plotted the missing mass for gamma d -> pi- p (X) which then
> should correspond to the other proton, as a function of the polar
> angle of the missing proton. The reference frame is the lab.
> Do you want me to repeat the procedure for the missing pion? Or do
> you want to see the missing mass versus the measured angles instead
> of the missing ones?

> Irene

> On Apr 24, 2014, at 4:00 PM, Eugene Pasyuk < pasyuk at jlab.org > wrote:

> > Hi Irene,
> 

> > Looks nice. A couple of questions.
> 
> > For which particle is this angle or you put both pion and proton
> > angle in the same histogram? Is it the lab angle or center of mass
> > angle? It would be good to see this in a lab frame separately for
> > pion angle and for proton angle. Can you do this?
> 

> > Thanks,
> 

> > -Eugene
> 

> > ----- Original Message -----
> 

> > > From: "Irene Zonta" < irene.zonta at roma2.infn.it >
> > 
> 
> > > To: "A.M. Sandorfi" < sandorfi at jlab.org >, pasyuk at jlab.org ,
> > > "Annalisa D'Angelo" < annalisa.dangelo at roma2.infn.it >,
> > > daoh at andrew.cmu.edu , "Peng Peng" < pp9e at virginia.edu >,
> > > hlu at jlab.org
> > 
> 
> > > Cc: "g14 run" < g14_run at jlab.org >
> > 
> 
> > > Sent: Thursday, April 24, 2014 9:33:36 AM
> > 
> 
> > > Subject: mmass vs polar angle
> > 
> 

> > > Dear all,
> > 
> 
> > > here is the result of the test that Eugene asked for, form the
> > > reaction gamma d -> pi- p (X). It looks like the correction is
> > > appropriate for every angle.
> > 
> 

> > > Cheers
> > 
> 

> > > Irene
> > 
> 
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