[G14_run] Al wires info.

[Tsuneo Kageya]

Ciao Alessandra,


 I give the info. Al wires for the three targets and I have a comment for Fig.29.

I am attaching a pdf file for HDIce technical note 23 (actual 23 is different from this,

as you can see on HDIce wiki page).


(a)  The diameters of Al wires and number of wires are as below;


 The lengths Al wires of three target cells are 6 cm, but the amounts of Al wires per cm are

proportional to the total areas of the wires:


(1) 21a: 51 um 769 wirea (0.002" = 2.54*0.002 = 0.0051 cm = 51 um)

(2) 19b: 38 um 965 wires

(3) 22b: 51 um 732 wires



 Ratio to total area of 19b to 21a:



   pi*38/2*38/2*965/(pi*51/2*51/2*769) = 0.697



 Ratio to total area of 22b to 21a:



   pi*51/2*51/2*732/(pi*51/2*51/2*769) = 0.952


 These numbers are close to those in the forth row of the  table at page 10.

The difference may come from the final number of wires.



 If use the narrow z vertex cut like yours (-9.5 < z < -5.8 cm), the ratio of Al wires

contribution of 19b to 21a is just 0.7.



(b) If you would like to do discussions using Fig. 29 in your note, you may see better

way of separating contributions of Al wires from Kel-F windows in the empty targets

shown at page 11 and 12 in the attachment.

Instead of one gaussian, three gaussians may well reproduce the Kel-F distributions.

At the vertex z > -4.8 cm, Kel-F is supposed to have more contriubutions than Al wires,

if assume both have same width of resolutions.  This is my opinion.


    Ciao, Tsuneo Kageya.


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