[G14_run] [EXTERNAL] Re: Al wires info.
Alessandra Filippi
filippi at to.infn.it
Wed May 10 04:35:45 EDT 2023
Hi Tsuneo,
thank you very much for all the infos and the note that you provided, I'll
work it out. Indeed (at least) a third gaussian for the Kel-F contribution
is needed in the fit, I'll try to add it taking into account your observations.
Also thanks to Andy for his last week's remarks.
Cheers
Alessandra
On Tue, 9 May 2023, Tsuneo Kageya wrote:
>
> Ciao Alessandra,
>
>
> I give the info. Al wires for the three targets and I have a comment for Fig.29.
>
> I am attaching a pdf file for HDIce technical note 23 (actual 23 is different from this,
>
> as you can see on HDIce wiki page).
>
>
> (a) The diameters of Al wires and number of wires are as below;
>
>
> The lengths Al wires of three target cells are 6 cm, but the amounts of Al wires per cm are
>
> proportional to the total areas of the wires:
>
>
> (1) 21a: 51 um 769 wirea (0.002" = 2.54*0.002 = 0.0051 cm = 51 um)
>
> (2) 19b: 38 um 965 wires
>
> (3) 22b: 51 um 732 wires
>
>
>
> Ratio to total area of 19b to 21a:
>
>
>
> pi*38/2*38/2*965/(pi*51/2*51/2*769) = 0.697
>
>
>
> Ratio to total area of 22b to 21a:
>
>
>
> pi*51/2*51/2*732/(pi*51/2*51/2*769) = 0.952
>
>
> These numbers are close to those in the forth row of the table at page 10.
>
> The difference may come from the final number of wires.
>
>
>
> If use the narrow z vertex cut like yours (-9.5 < z < -5.8 cm), the ratio of Al wires
>
> contribution of 19b to 21a is just 0.7.
>
>
>
> (b) If you would like to do discussions using Fig. 29 in your note, you may see better
>
> way of separating contributions of Al wires from Kel-F windows in the empty targets
>
> shown at page 11 and 12 in the attachment.
>
> Instead of one gaussian, three gaussians may well reproduce the Kel-F distributions.
>
> At the vertex z > -4.8 cm, Kel-F is supposed to have more contriubutions than Al wires,
>
> if assume both have same width of resolutions. This is my opinion.
>
>
> Ciao, Tsuneo Kageya.
>
>
>
>
>
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