[Hps-ecal] Opening angle from Ecal

Stepan Stepanyan stepanya at jlab.org
Fri Jan 9 12:06:55 EST 2015


Hi Holly,

Also do not forget that integral field that is used may not be exactly 
what we
have in real life. So, new simulations may be needed to get 
parametrization correct.

Stepan
On 1/9/15 12:03 PM, Holly Vance wrote:
> Hi Michel,
>
> Thank you for your response. Indeed, you are correct-it is misleading 
> to write cluster energy since what I used was the thrown monte carlo 
> energy. FX sent me some suggestions for checking the residuals 
> (phi_calc - phi_generated), and the actual resolution will contain the 
> spread from the position and energy as measured. It is very nice to 
> see that all of this supports the plots from simulation in the HPS 
> Note 2014-001.
>
> Respectfully,
> Holly
>
> On Fri, Jan 9, 2015 at 6:17 AM, Garcon Michel <Michel.Garcon at cea.fr 
> <mailto:Michel.Garcon at cea.fr>> wrote:
>
>     Hi Holly,
>
>     Nice study. It is a bit counter-intuitive to call Phi a
>     (projected) horizontal angle and Theta a vertical angle, but this
>     is a minor detail.
>
>     One does expect indeed dPhi/dx = dTheta/dx ~ 1/D ~ 1/1.4 m ~ 0.007
>     radian/cm . In the vertical projection, the trajectory is a 
>     straight line whatever the energy (for an ideal field), which
>     explains that you find no energy dependence for Theta. In the
>     horizontal projection, your line in the first plot Phi vs x at 1
>     GeV is the same as the light blue in Fig. 31 of HPS-Note-2014-001
>     (one can see also in this figure that the slope does not depend on
>     energy). So everything checks nicely.
>
>     I would expect B = 0 when E goes to infinity (straight line -> x =
>     0 when Phi =0). But you are right to do whatever empirical fit
>     works in our range.
>
>     Best regards,
>
>     Michel.
>
>     PS: by cluster energy, do you mean deposited energy in ECal or
>     real energy? I would imagine the latter since you generate
>     particles at fixed energies; then better not call it cluster
>     energy, could be confusing (see Eqs 1 and 2 of the Note).
>
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