[Clas_hadron] dnp presentation

[Biplab Dey]

> In slide 6, \hat{n} is shown as \hat{gamma} \times \hat{Sigma}. Isn't \hat{n} 
> = \hat{gamma} \times \hat{K} for the recoil polarization?

I thought about it a bit more. I think if \hat{n} was taken as \hat{gamma} 
\times \hat{Sigma}, then an extra -ve sign will be required, because the 
*definition* of P_y is +ve \hat{y} points along  \hat{gamma} \times 
\hat{meson}. Unless of course, this is taken care of elsewhere in the 
code.

-Biplab